Tokenizer: Fix syntax error when operator* is called

lib/tokenize.cpp

@@ -11080,6 +11080,11 @@ void Tokenizer::simplifyOperatorName()
         if (tok->str() != "operator")
             continue;
         // operator op
+        if (Token::Match(tok, "operator %op% (")) {
+            tok->str(tok->str() + tok->next()->str());
+            tok->deleteNext();
+            continue;
+        }
         std::string op;
         Token *par = tok->next();
         bool done = false;

test/testtokenize.cpp

@@ -412,6 +412,7 @@ private:
         TEST_CASE(simplifyOperatorName23);
         TEST_CASE(simplifyOperatorName24);
         TEST_CASE(simplifyOperatorName25);
+        TEST_CASE(simplifyOperatorName26);
 
         TEST_CASE(simplifyNullArray);
 
@@ -6602,6 +6603,14 @@ private:
                       tokenizeAndStringify(code));
     }
 
+    void simplifyOperatorName26() {
+        const char code[] = "void foo() {"
+                            "    x = y.operator *().z[123];"
+                            "}";
+        ASSERT_EQUALS("void foo ( ) { x = y . operator* ( ) . z [ 123 ] ; }",
+                      tokenizeAndStringify(code));
+    }
+
     void simplifyNullArray() {
         ASSERT_EQUALS("* ( foo . bar [ 5 ] ) = x ;", tokenizeAndStringify("0[foo.bar[5]] = x;"));
     }