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better fix for #3114 (infinite recursion when operator= is overloaded)

This commit is contained in:
Robert Reif 2011-09-14 19:58:11 -04:00
parent 2bc7da2c64
commit 2670525b4f
1 changed files with 17 additions and 16 deletions
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33
lib/checkclass.cpp
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@ -378,6 +378,15 @@ void CheckClass::initializeVarList(const Function &func, std::list<std::string>
else if (Token::simpleMatch(ftok, "operator= (") &&
ftok->previous()->str() != "::")
{
// recursive call / calling overloaded function
// assume that all variables are initialized
if (std::find(callstack.begin(), callstack.end(), ftok->str()) != callstack.end())
{
/** @todo false negative: just bail */
assignAllVar(usage);
return;
}
/** @todo check function parameters for overloaded function so we check the right one */
// check if member function exists
std::list<Function>::const_iterator it;
@ -393,14 +402,10 @@ void CheckClass::initializeVarList(const Function &func, std::list<std::string>
// member function has implementation
if (it->hasBody)
{
// check for recursion
if ((&(*it) != &func))
{
// initialize variable use list using member function
callstack.push_back(ftok->str());
initializeVarList(*it, callstack, scope, usage);
callstack.pop_back();
}
// initialize variable use list using member function
callstack.push_back(ftok->str());
initializeVarList(*it, callstack, scope, usage);
callstack.pop_back();
}
// there is a called member function, but it has no implementation, so we assume it initializes everything
@ -450,14 +455,10 @@ void CheckClass::initializeVarList(const Function &func, std::list<std::string>
// member function has implementation
if (it->hasBody)
{
// check for recursion
if ((&(*it) != &func))
{
// initialize variable use list using member function
callstack.push_back(ftok->str());
initializeVarList(*it, callstack, scope, usage);
callstack.pop_back();
}
// initialize variable use list using member function
callstack.push_back(ftok->str());
initializeVarList(*it, callstack, scope, usage);
callstack.pop_back();
}
// there is a called member function, but it has no implementation, so we assume it initializes everything