Fixed #2452 (syntax error when 'void f(typedef int x)' is used. causes segmentation fault.)

This commit is contained in:
Robert Reif 2011-01-14 07:41:22 +01:00 committed by Daniel Marjamäki
parent 012b07023b
commit 708a75e363
2 changed files with 16 additions and 0 deletions

View File

@ -856,6 +856,13 @@ void Tokenizer::simplifyTypedef()
else if (tok->str() != "typedef")
continue;
// check for syntax errors
if (tok->previous() && tok->previous()->str() == "(")
{
syntaxError(tok);
continue;
}
// pull struct, union, enum or class definition out of typedef
// use typedef name for unnamed struct, union, enum or class
if (Token::Match(tok->next(), "const| struct|enum|union|class %type% {") ||

View File

@ -233,6 +233,7 @@ private:
TEST_CASE(simplifyTypedef73); // ticket #2412
TEST_CASE(simplifyTypedef74); // ticket #2414
TEST_CASE(simplifyTypedef75); // ticket #2426
TEST_CASE(simplifyTypedef76); // ticket #2453
TEST_CASE(simplifyTypedefFunction1);
TEST_CASE(simplifyTypedefFunction2); // ticket #1685
@ -4795,6 +4796,14 @@ private:
ASSERT_EQUALS("", errout.str());
}
void simplifyTypedef76() // ticket #2453 segmentation fault
{
const char code[] = "void f1(typedef int x) {}\n";
const std::string expected = "void f1 ( typedef int x ) { }";
ASSERT_EQUALS(expected, sizeof_(code));
ASSERT_EQUALS("[test.cpp:1]: (error) syntax error\n", errout.str());
}
void simplifyTypedefFunction1()
{
{