Tokenizer: Improved simplification of 'a?(1):b'
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@ -6586,6 +6586,18 @@ bool Tokenizer::simplifyRedundantParenthesis()
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continue;
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}
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if (Token::simpleMatch(tok->previous(), "? (") && Token::simpleMatch(tok->link(), ") :")) {
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const Token *tok2 = tok->next();
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while (tok2 && (tok2->isName() || tok2->isNumber() || tok2->isBoolean() || tok2->isArithmeticalOp()))
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tok2 = tok2->next();
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if (tok2 && tok2->str() == ")") {
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tok->link()->deleteThis();
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tok->deleteThis();
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ret = true;
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continue;
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}
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}
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while (Token::Match(tok->previous(), "[{([,:] ( !!{") && Token::Match(tok->link(), ") [;,])]")) {
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// We have "( ... )", remove the parenthesis
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tok->link()->deleteThis();
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@ -4574,6 +4574,7 @@ private:
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void removeParentheses15() {
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ASSERT_EQUALS("a = b ? c : 123 ;", tokenizeAndStringify("a = b ? c : (123);", false));
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ASSERT_EQUALS("a = b ? c : 579 ;", tokenizeAndStringify("a = b ? c : ((123)+(456));", false));
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ASSERT_EQUALS("a = b ? 123 : c ;", tokenizeAndStringify("a = b ? (123) : c;", false));
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}
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void tokenize_double() {
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