[iter] Disable operator +
To see if it makes bots happy... This is frustrating.
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@ -75,7 +75,8 @@ struct hb_iter_t
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iter_t& operator ++ () { thiz()->__next__ (); return *thiz(); }
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iter_t& operator -= (unsigned count) { thiz()->__rewind__ (count); return *thiz(); }
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iter_t& operator -- () { thiz()->__prev__ (); return *thiz(); }
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iter_t operator + (unsigned count) const { iter_t c (*thiz()); c += count; return c; }
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//TODO(C++11)iter_t operator + (unsigned count) const { iter_t c (*thiz()); c += count; return c; }
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//TODO(C++11)friend iter_t operator + (unsigned count, const iter_t &it) { return it + count; }
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iter_t operator ++ (int) { iter_t c (*thiz()); ++*thiz(); return c; }
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iter_t operator - (unsigned count) const { iter_t c (*thiz()); c -= count; return c; }
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iter_t operator -- (int) { iter_t c (*thiz()); --*thiz(); return c; }
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@ -102,7 +103,7 @@ struct hb_iter_t
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using Name::operator ++; \
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using Name::operator -=; \
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using Name::operator --; \
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using Name::operator +; \
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/*TODO(C++11)using Name::operator +;*/ \
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using Name::operator -; \
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using Name::is_random_access; \
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static_assert (true, "")
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@ -74,8 +74,9 @@ test_iterator (Iterator it)
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for (auto c = it.iter (); c; c++)
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*c;
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it += it.len () + 10;
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it = it + 10;
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it += it.len ();
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//TODO(C++11)it = it + 10;
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//TODO(C++11)it = 10 + it;
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assert (*it == it[0]);
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