[uniscribe] Ask Uniscribe to return shaping results in logical order
See discussion on the list in the thread "Arabic presentation forms and the uniscribe backend". Based on patch from Jonathan Kew.
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@ -832,9 +832,8 @@ retry:
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unsigned int glyphs_offset = 0;
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unsigned int glyphs_len;
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bool backward = HB_DIRECTION_IS_BACKWARD (buffer->props.direction);
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for (unsigned int j = 0; j < item_count; j++)
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for (unsigned int i = 0; i < item_count; i++)
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{
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unsigned int i = backward ? item_count - 1 - j : j;
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unsigned int chars_offset = items[i].iCharPos;
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unsigned int item_chars_len = items[i + 1].iCharPos - chars_offset;
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@ -875,6 +874,10 @@ retry:
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}
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}
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/* Asking for glyphs in logical order circumvents at least
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* one bug in Uniscribe. */
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items[i].a.fLogicalOrder = true;
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retry_shape:
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hr = funcs->ScriptShapeOpenType (font_data->hdc,
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&font_data->script_cache,
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@ -962,15 +965,9 @@ retry:
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uint32_t *p = &vis_clusters[log_clusters[buffer->info[i].utf16_index()]];
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*p = MIN (*p, buffer->info[i].cluster);
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}
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if (!backward) {
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for (unsigned int i = 1; i < glyphs_len; i++)
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if (vis_clusters[i] == -1)
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vis_clusters[i] = vis_clusters[i - 1];
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} else {
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for (int i = glyphs_len - 2; i >= 0; i--)
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if (vis_clusters[i] == -1)
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vis_clusters[i] = vis_clusters[i + 1];
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}
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for (unsigned int i = 1; i < glyphs_len; i++)
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if (vis_clusters[i] == -1)
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vis_clusters[i] = vis_clusters[i - 1];
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#undef utf16_index
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@ -1004,10 +1001,13 @@ retry:
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/* TODO vertical */
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pos->x_advance = info->mask;
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pos->x_offset = info->var1.u32;
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pos->x_offset = backward ? -info->var1.u32 : info->var1.u32;
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pos->y_offset = info->var2.u32;
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}
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if (backward)
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hb_buffer_reverse (buffer);
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/* Wow, done! */
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return true;
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}
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