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[subset-cff] Immediately drop subr numbers instead of marking for skip 

Seems to work and saves ~2% time.
This commit is contained in:
Behdad Esfahbod 2022-11-26 18:18:35 -07:00
parent 1cf4f3e083
commit 69ce606d14
1 changed files with 2 additions and 15 deletions
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17
src/hb-subset-cff-common.hh
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@ -304,21 +304,16 @@ struct parsed_cs_op_t : op_str_t
{
subr_num = subr_num_;
drop_flag = false;
skip_flag = false;
}
bool for_drop () const { return drop_flag; }
void set_drop () { drop_flag = true; }
bool for_skip () const { return skip_flag; }
void set_skip () { skip_flag = true; }
/* The layout of this struct is designed to fit within the
* padding of op_str_t! */
protected:
bool drop_flag : 1;
bool skip_flag : 1;
public:
uint16_t subr_num;
@ -349,15 +344,7 @@ struct parsed_cs_str_t : parsed_values_t<parsed_cs_op_t>
unsigned int parsed_len = get_count ();
if (likely (parsed_len > 0))
{
values[parsed_len-1].set_skip ();
/* Note(behdad): Alternatively, we can pop the subr number completely instead?
* Seems to work. Then we can remove set_skip/is_skip completely. That would
* change the design of this object that the ops won't be contiguous anymore.
* I don't think that's a problem. Maybe switch this one day. */
//values.pop ();
}
values.pop ();
parsed_cs_op_t val;
val.init (subr_num);
@ -1018,7 +1005,7 @@ struct subr_subsetter_t
for (unsigned int i = 0; i < count; i++)
{
const parsed_cs_op_t &opstr = arr[i];
if (!opstr.for_drop () && !opstr.for_skip ())
if (!opstr.for_drop ())
{
switch (opstr.op)
{