Don't use "operator ="

Some compilers don't like operator = defined on members of union members
either.  Reported by Ginn Chen for Sun Studio compilers.
This commit is contained in:
Behdad Esfahbod 2010-07-23 14:46:57 -04:00
parent 39fe34d4c3
commit 81408cd51c
1 changed files with 3 additions and 3 deletions

View File

@ -370,7 +370,7 @@ template <typename Type>
class BEInt<Type, 2>
{
public:
inline class BEInt<Type,2>& operator = (Type i) { hb_be_uint16_put (v,i); return *this; }
inline void set (Type i) { hb_be_uint16_put (v,i); }
inline operator Type () const { return hb_be_uint16_get (v); }
inline bool operator == (const BEInt<Type, 2>& o) const { return hb_be_uint16_cmp (v, o.v); }
inline bool operator != (const BEInt<Type, 2>& o) const { return !(*this == o); }
@ -380,7 +380,7 @@ template <typename Type>
class BEInt<Type, 4>
{
public:
inline class BEInt<Type,4>& operator = (Type i) { hb_be_uint32_put (v,i); return *this; }
inline void set (Type i) { hb_be_uint32_put (v,i); }
inline operator Type () const { return hb_be_uint32_get (v); }
inline bool operator == (const BEInt<Type, 4>& o) const { return hb_be_uint32_cmp (v, o.v); }
inline bool operator != (const BEInt<Type, 4>& o) const { return !(*this == o); }
@ -391,7 +391,7 @@ class BEInt<Type, 4>
template <typename Type>
struct IntType
{
inline void set (Type i) { v = i; }
inline void set (Type i) { v.set (i); }
inline operator Type(void) const { return v; }
inline bool operator == (const IntType<Type> &o) const { return v == o.v; }
inline bool operator != (const IntType<Type> &o) const { return v != o.v; }