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Further small fix to regerror() overflow handling, to ensure identical output 

whether or not there is a zero at the end of the buffer.
This commit is contained in:
Philip.Hazel 2016-02-28 13:33:55 +00:00
parent 371bf87af6
commit 21ca32717f
1 changed files with 5 additions and 1 deletions
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6
src/pcre2test.c
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@ -4780,7 +4780,11 @@ if ((pat_patctl.control & CTL_POSIX) != 0)
memcpy(pbuffer8 + bsize, "DEADBEEF", 8); memcpy(pbuffer8 + bsize, "DEADBEEF", 8);
usize = regerror(rc, &preg, (char *)pbuffer8, bsize); usize = regerror(rc, &preg, (char *)pbuffer8, bsize);
psize = (int)bsize; /* Inside regerror(), snprintf() is used. If the buffer is too small, some
versions of snprintf() put a zero byte at the end, but others do not.
Therefore, we print a maximum of one less than the size of the buffer. */
psize = (int)bsize - 1;
fprintf(outfile, "Failed: POSIX code %d: %.*s\n", rc, psize, pbuffer8); fprintf(outfile, "Failed: POSIX code %d: %.*s\n", rc, psize, pbuffer8);
if (usize > bsize) if (usize > bsize)
{ {