Don't ignore {1}+ when it is applied to a parenthesized item.
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@ -61,6 +61,11 @@ addition (a) the default limit for groups requested by -o<n> has been raised to
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50, (b) the new --om-capture option changes the limit, (c) an error is raised
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if -o asks for a group that is above the limit.
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12. The quantifier {1} was always being ignored, but this is incorrect when it
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is made possessive and applied to an item in parentheses, because a
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parenthesized item may contain multiple branches or other backtracking points,
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for example /(a|ab){1}+c/ or /(a+){1}+a/.
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Version 10.33 16-April-2019
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---------------------------
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@ -6758,10 +6758,6 @@ for (;; pptr++)
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reqvary = (repeat_min == repeat_max)? 0 : REQ_VARY;
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op_type = 0;
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/* If the repeat is {1} we can ignore it. */
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if (repeat_max == 1 && repeat_min == 1) goto END_REPEAT;
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/* Adjust first and required code units for a zero repeat. */
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if (repeat_min == 0)
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@ -6804,7 +6800,10 @@ for (;; pptr++)
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tempcode = previous;
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op_previous = *previous;
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/* Now handle repetition for the different types of item. */
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/* Now handle repetition for the different types of item. If the repeat
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minimum and the repeat maximum are both 1, we can ignore the quantifier for
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non-parenthesized items, as they have only one alternative. For anything in
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parentheses, we must not ignore if {1} is possessive. */
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switch (op_previous)
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{
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@ -6818,6 +6817,7 @@ for (;; pptr++)
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case OP_CHARI:
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case OP_NOT:
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case OP_NOTI:
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if (repeat_max == 1 && repeat_min == 1) goto END_REPEAT;
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op_type = chartypeoffset[op_previous - OP_CHAR];
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/* Deal with UTF characters that take up more than one code unit. */
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@ -6864,6 +6864,7 @@ for (;; pptr++)
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code = previous;
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goto END_REPEAT;
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}
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if (repeat_max == 1 && repeat_min == 1) goto END_REPEAT;
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if (repeat_min == 0 && repeat_max == REPEAT_UNLIMITED)
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*code++ = OP_CRSTAR + repeat_type;
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@ -6898,6 +6899,8 @@ for (;; pptr++)
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repetition. */
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case OP_RECURSE:
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if (repeat_max == 1 && repeat_min == 1 && !possessive_quantifier)
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goto END_REPEAT;
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/* Generate unwrapped repeats for a non-zero minimum, except when the
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minimum is 1 and the maximum unlimited, because that can be handled with
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@ -6980,6 +6983,9 @@ for (;; pptr++)
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PCRE2_UCHAR *bralink = NULL;
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PCRE2_UCHAR *brazeroptr = NULL;
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if (repeat_max == 1 && repeat_min == 1 && !possessive_quantifier)
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goto END_REPEAT;
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/* Repeating a DEFINE group (or any group where the condition is always
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FALSE and there is only one branch) is pointless, but Perl allows the
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syntax, so we just ignore the repeat. */
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@ -7196,11 +7202,12 @@ for (;; pptr++)
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and SCRIPT_RUN groups at runtime, but in a different way.]
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Then, if the quantifier was possessive and the bracket is not a
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conditional, we convert the BRA code to the POS form, and the KET code to
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KETRPOS. (It turns out to be convenient at runtime to detect this kind of
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subpattern at both the start and at the end.) The use of special opcodes
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makes it possible to reduce greatly the stack usage in pcre2_match(). If
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the group is preceded by OP_BRAZERO, convert this to OP_BRAPOSZERO.
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conditional, we convert the BRA code to the POS form, and the KET code
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to KETRPOS. (It turns out to be convenient at runtime to detect this
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kind of subpattern at both the start and at the end.) The use of
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special opcodes makes it possible to reduce greatly the stack usage in
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pcre2_match(). If the group is preceded by OP_BRAZERO, convert this to
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OP_BRAPOSZERO.
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Then, if the minimum number of matches is 1 or 0, cancel the possessive
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flag so that the default action below, of wrapping everything inside
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@ -7301,6 +7308,8 @@ for (;; pptr++)
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int prop_type, prop_value;
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PCRE2_UCHAR *oldcode;
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if (repeat_max == 1 && repeat_min == 1) goto END_REPEAT;
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op_type = OP_TYPESTAR - OP_STAR; /* Use type opcodes */
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mclength = 0; /* Not a character */
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@ -6351,4 +6351,18 @@ ef) x/x,mark
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acb
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abc
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/(?:a|ab){1}+c/
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\= Expect no match
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abc
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/(a|ab){1}+c/
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abc
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/(a+){1}+a/
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\= Expect no match
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aaaa
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/(?(DEFINE)(a|ab))(?1){1}+c/
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abc
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# End of testinput1
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@ -10063,4 +10063,22 @@ MK: 2
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0: a
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MK: 2
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/(?:a|ab){1}+c/
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\= Expect no match
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abc
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No match
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/(a|ab){1}+c/
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abc
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No match
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/(a+){1}+a/
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\= Expect no match
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aaaa
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No match
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/(?(DEFINE)(a|ab))(?1){1}+c/
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abc
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No match
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# End of testinput1
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